处于重力场中的单摆,在摆角不大(θ<5°)时,作简谐振动。振动的中心平衡位置,为单摆摆球处于静止时的摆绳位置(即重垂线方向)。振动周期 T=2π(L/g)~(1/2),其中 L 为摆长,g 为重力加速度。g 值可用单摆处于静止时的摆绳张力 F(即摆球处于平衡时,观察者所看到的系于摆绳上的弹簧秤读数)与摆球质量 m 之比F/m=G~*/m来确定。这比值可称为“视重加速度”。现将此单摆摆球带上电量 q(q>0)后置于稳恒匀强电场 E 中,其摆动是否仍是简谐振动?如仍作简谐振动,则振动周期又是多大?对 The pendulum in the gravitational field performs simple harmonic vibration when the swing angle is not large (θ<5°). The center balance position of the vibration is the position of the swing rope when the pendulum ball is at rest (ie, the direction of the vertical line). Vibration period T=2π(L/g)~(1/2), where L is the pendulum length and g is the gravitational acceleration. The value of g is the ratio of the tension of the swing rope F when the pendulum is at rest (the balance of the spring scale reading seen by the observer when the pendulum ball is in balance) and the mass m of the pendulum ball F/m=G~* /m to determine. This ratio can be referred to as “visual acceleration.” Now put this single oscillating pendulum ball on the electric quantity q (q>0) and place it in a stable and uniform electric field E. Is the oscillation still harmonic vibration? If it is still simple harmonic vibration, how large is the vibration period? Correct